Python calling a (fortran) library that uses MPI -

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I would like to call and call a library which uses MPI, I think that each rank has its own version of the library Loads and then the library will communicate with each other. I do not want to do any communication or MPI handling with the library collar. Python code will not be the same if I load a library that uses an MPI or a library which uses openmp for example.

MCA Base: Component_find: unable to open the / usr / lib / openmpi / I manage to make it work when I dynamically load and library calls C but failed with Python Lib / Openmpi / mca_paffinity_hwloc: Probably unavailable symbol, or compiled for a different version of Open MPI? (Ignored)

[..]

It seems that opal_init has failed for some reason;

[..]

failed opal_shmem_base_select -> the value -1 OPAL_SUCCESS instead ompi_mpi_init: failed orte_init -> Back "Error" (- 1) Instead of "Success" (0)

[..]

I wonder what to do with the dragon Is there anything like copyping the dragon with OpenMPi?

I give an example below:

testMPI.py 

  #! / Usr / bin / ctypes from env python import * # loading library raw = cdll.LoadLibrary ( './ libtest.so.1.0') print "Hello World" raw.test ()

test.f90 

  suburban test () bind (c, name = 'test') MPI built-in integer :: nprocs = 1! & Lt; Total number of process integer :: post = 0! & Lt; Comm world in the rank: Integer :: IARR = 1! & Lt; Phone MPI_init (ierr) MPI_comm_size call (MPI_comm_world, nprocs, ierr) call MPI_comm_rank (MPI_comm_world, rank, ierr) write (*, *) "" World Hello, rank, "the", nprocs MPI_finalize call (ierr) end subroutine < / code>

Makefile 

  FC = mpif90.openmpi FFLAGS = -free -fPIC G -Wall all: obj test: mpirun. openmpi -n 4 ./testMPI.py obj: $ (FC) $ (FFLAGS) -c test.f90 $ (FC) $ (FFLAGS) are shared -Wl, -soname, libtest.so.1 -o libtest. So.1.0 test.o clean: rm * .o libtest *

I have a Similar issues are a thing for this: When you configure for openmpi compilation, use the following flag:

./configure --disable-dlopen

Hope this works you!


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