java - separate the two matches -

Rex problem: I want to get the group twice, but I do not know how to solve it.

Here is the code:

  public static zero multiGroupTest () {// pattern p = pattern.compile ("(\\ w +) (\\ d \\ D) (\\ w +) "); Pattern p = Pattern.compile ("([A-Z] {1}) (\\ d +) ([A-Za-z] +)"); String str = "X89SuperJavaJavaX89SuperJava"; Mitcher M = P. Matcher (str); While (m.find ()) {System.out.println (m.group (1)); Println (m.group (2)); Println (m.group (3)); Okay, the result is:  
  x 89 super java java x  
 
 What do I get to: 
 
  X 89 Super Jawazawa X 89 Super Java How can I separate two matches?   
 
 
 because the last group  ([A-Za-z] +)  greed Will match the following X, you could not get two wire. Use  ((?: [AZ] [az] +) + /  to capture the words contained in the  FooBar  format, because the name does not end with a capital letter Will be 
 
  ([AZ]) (\\ d +) ((?: [AZ] [az] +) +)  
 
 
 
  pattern p = pattern.compile ("([AZ]) (\\ d +) ((?: [AZ] [az] +) +); String str = "X89SuperJavaJavaX89SuperJava"; Mitcher M = P. Matcher (str); While (m.find ()) {System.out.println (m.group (1)); Println (m.group (2)); Println (m.group (3)); }  
 
  Output:  
 
  X 89 super java java x 89 super java