linux - check if the input is a vowel -

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I am beginning with Bash scripting and which I have studied in other programming languages, most of them apply For bash I have to check whether the user has entered a vowel or not. I came up with this: 

  #! / Bin / bash read -p "Enter something:" char if [[$ char -eq [AEIOUEiou] *]]; Then the "vowels" resonate the other "consonant" fix

but when I run it on IdeOne, I get an error: 

  Prog.sh: line 3: [[: [AiUUEUU] *: Syntax error: Operand expected (error token is "[AEUUEUU] *")

Can anyone tell me that What is wrong here and how to improve it?

I know that many other conditions should not be cleaned together in a clean way. I am trying to avoid it.

you == operator to match this globe: 

  #! / Bin / bash read -p "Enter something:" char if [["$ char" == * [AYUU]]] ;; Then the "vowel" is used to match the second "Exonontant" fix

-a -

Test according to man : 

  INTEGER1 -Ec INTEGER2 is equal to INTEGER1 INTEGER2

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