xampp 1.8.3 with PHP 5.5.15 - SID variable is undefined -


Good day every,

I'm running XAMPP 1.8.3 with PHP 5.5.15, And when I point out my browser (the latest version of Chrome or Firefox), the following error:

Notice: Undefined variable: in SID ... \ index.php on line 1 < / P>

The first line of the index looks like the following:

  & lt ;? Php if (! ($ SID)) {session_start (); }? & Gt;  

This code is used to work in previous versions of PHP (4.xx).

After some online search, I found out that I need to set session.use_trans_sid instead of 0 (default) I did this, but the problem still persists

Does anyone know why this is happening?

Thanks in advance,


Comments

Popular posts from this blog

HTML/CSS - Automatically set height width from background image? -

php - Mysql Show Process - Sleep Commands and what to do -

c - What is the address of buf (the local variable in the main function)? -