r - store rows of a data.frame are equal to top.20. in frequens from column as factor i.e names -

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data.fr (d1.csv) looks like this: 

  Weight 23 170 60 Judo 33 193 125 Athletics

Let me introduce a new data like D2 with the top 20. Frame will be created 

  name (top 20. source) [1] "athletics" "swimming" "football" "rowing"

... and Use it to use match () or % in% subset () such as D1 with subset = game %% names (top .20.sports)

I have tried many things, I'm new on this and I'm missing something ... 

  d2 < -subset (d1, (% in game% name (above .20.sports)))

returns a hole list, like 

  d2 and lt ; - d1 [d1 $ Sport% name matches

match me "NA" 

  d2 < -d1 [, tolower (name) gives a bunch (name) (top.20.sports)) in% d1 [, 4]] with dataframe 0 colomon and 9038 rows
< P> (9038 rows are the right bud where the data is?)

< P>

I sleep Was that I have 10,384 rows

-10384 24 221 110 Basketball -

basketball in the final. Number of lines in the row is not the number of rows:

nrow (d2)

[1] 800 9

Dim (D2)

[1] 800 9 4


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