playframework 2.0 - Drop value from Play Json -

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मेरे पास Play में एक केस क्लास है: 

  केस वर्ग हवाई अड्डा (नाम: स्ट्रिंग, प्रारूप [स्ट्रिंग] और (जेएसपीथ \ "आईटा") प्रारूप [स्ट्रिंग] और (जेएसपीथ \ "देश")। प्रारूप [स्ट्रिंग]) (हवाईअड्डाअटो कॉम्पलेट.अप्ली, अनलिफ्ट (एयरपोर्टअटो कॉम्पलेट.अनुप्ली))}

अब मैं एक हवाई अड्डे को ठीक से भेजना चाहता हूं (जेसन। टॉसन (..)) प्रतिक्रिया । लेकिन मैं देश को स्ट्रिंग भेजना नहीं चाहता। क्या मैं इसे किसी तरह छोड़ सकता हूं?

संपादित करें: कार्य समाधान ठीक है (जेसन.टी.जसन (एयरपोर्टलिस्ट.मैप (जेसन। टोजसन (_)। [जेएसओबाइज] - "देश"))

आपको -

का उपयोग करना चाहिए x नाम का एक वैल, आप निम्न कोड का प्रयोग करेंगे:

ठीक है (जेसन। टोजसन (एक्स) - "देश")

JsObject Scaladoc से:


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